Optimal. Leaf size=74 \[ -\frac{i x \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^2}+\frac{\text{PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^3}+\frac{x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i x^3}{3} \]
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Rubi [A] time = 0.140043, antiderivative size = 74, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {3717, 2190, 2531, 2282, 6589} \[ -\frac{i x \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{b^2}+\frac{\text{PolyLog}\left (3,e^{2 i (a+b x)}\right )}{2 b^3}+\frac{x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i x^3}{3} \]
Antiderivative was successfully verified.
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Rule 3717
Rule 2190
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int x^2 \cot (a+b x) \, dx &=-\frac{i x^3}{3}-2 i \int \frac{e^{2 i (a+b x)} x^2}{1-e^{2 i (a+b x)}} \, dx\\ &=-\frac{i x^3}{3}+\frac{x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{2 \int x \log \left (1-e^{2 i (a+b x)}\right ) \, dx}{b}\\ &=-\frac{i x^3}{3}+\frac{x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i x \text{Li}_2\left (e^{2 i (a+b x)}\right )}{b^2}+\frac{i \int \text{Li}_2\left (e^{2 i (a+b x)}\right ) \, dx}{b^2}\\ &=-\frac{i x^3}{3}+\frac{x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i x \text{Li}_2\left (e^{2 i (a+b x)}\right )}{b^2}+\frac{\operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^3}\\ &=-\frac{i x^3}{3}+\frac{x^2 \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{i x \text{Li}_2\left (e^{2 i (a+b x)}\right )}{b^2}+\frac{\text{Li}_3\left (e^{2 i (a+b x)}\right )}{2 b^3}\\ \end{align*}
Mathematica [A] time = 0.418272, size = 136, normalized size = 1.84 \[ \frac{6 i b x \text{PolyLog}\left (2,-e^{-i (a+b x)}\right )+6 i b x \text{PolyLog}\left (2,e^{-i (a+b x)}\right )+6 \text{PolyLog}\left (3,-e^{-i (a+b x)}\right )+6 \text{PolyLog}\left (3,e^{-i (a+b x)}\right )+3 b^2 x^2 \log \left (1-e^{-i (a+b x)}\right )+3 b^2 x^2 \log \left (1+e^{-i (a+b x)}\right )+i b^3 x^3}{3 b^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.242, size = 198, normalized size = 2.7 \begin{align*} -{\frac{i}{3}}{x}^{3}+{\frac{\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}+1 \right ){x}^{2}}{b}}-{\frac{2\,i{\it polylog} \left ( 2,-{{\rm e}^{i \left ( bx+a \right ) }} \right ) x}{{b}^{2}}}+2\,{\frac{{\it polylog} \left ( 3,-{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{3}}}+{\frac{\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ){x}^{2}}{b}}-{\frac{\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ){a}^{2}}{{b}^{3}}}-{\frac{2\,i{\it polylog} \left ( 2,{{\rm e}^{i \left ( bx+a \right ) }} \right ) x}{{b}^{2}}}+2\,{\frac{{\it polylog} \left ( 3,{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{3}}}+{\frac{{a}^{2}\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}-1 \right ) }{{b}^{3}}}-2\,{\frac{{a}^{2}\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{3}}}+{\frac{{\frac{4\,i}{3}}{a}^{3}}{{b}^{3}}}+{\frac{2\,i{a}^{2}x}{{b}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.41069, size = 347, normalized size = 4.69 \begin{align*} -\frac{2 i \,{\left (b x + a\right )}^{3} - 6 i \,{\left (b x + a\right )}^{2} a + 12 i \, b x{\rm Li}_2\left (-e^{\left (i \, b x + i \, a\right )}\right ) + 12 i \, b x{\rm Li}_2\left (e^{\left (i \, b x + i \, a\right )}\right ) - 6 \, a^{2} \log \left (\sin \left (b x + a\right )\right ) -{\left (6 i \,{\left (b x + a\right )}^{2} - 12 i \,{\left (b x + a\right )} a\right )} \arctan \left (\sin \left (b x + a\right ), \cos \left (b x + a\right ) + 1\right ) -{\left (-6 i \,{\left (b x + a\right )}^{2} + 12 i \,{\left (b x + a\right )} a\right )} \arctan \left (\sin \left (b x + a\right ), -\cos \left (b x + a\right ) + 1\right ) - 3 \,{\left ({\left (b x + a\right )}^{2} - 2 \,{\left (b x + a\right )} a\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) + 1\right ) - 3 \,{\left ({\left (b x + a\right )}^{2} - 2 \,{\left (b x + a\right )} a\right )} \log \left (\cos \left (b x + a\right )^{2} + \sin \left (b x + a\right )^{2} - 2 \, \cos \left (b x + a\right ) + 1\right ) - 12 \,{\rm Li}_{3}(-e^{\left (i \, b x + i \, a\right )}) - 12 \,{\rm Li}_{3}(e^{\left (i \, b x + i \, a\right )})}{6 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 1.76703, size = 664, normalized size = 8.97 \begin{align*} \frac{-2 i \, b x{\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) + 2 i \, b x{\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right ) + 2 \, a^{2} \log \left (-\frac{1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) + \frac{1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac{1}{2}\right ) + 2 \, a^{2} \log \left (-\frac{1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) - \frac{1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac{1}{2}\right ) + 2 \,{\left (b^{2} x^{2} - a^{2}\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) + 2 \,{\left (b^{2} x^{2} - a^{2}\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) +{\rm polylog}\left (3, \cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) +{\rm polylog}\left (3, \cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right )}{4 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \cot{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \cot \left (b x + a\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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